-91=19+(3/5)k

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Solution for -91=19+(3/5)k equation: 



-91=19+(3/5)k

We move all terms to the left:

-91-(19+(3/5)k)=0



Domain of the equation: 5)k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

-(19+(+3/5)k)-91=0

We multiply all the terms by the denominator


-(19+(+3-91*5)k)=0



We calculate terms in parentheses: -(19+(+3-91*5)k), so:

19+(+3-91*5)k

determiningTheFunctionDomain
(+3-91*5)k+19

We add all the numbers together, and all the variables

(-452)k+19

We multiply parentheses

-452k+19

Back to the equation:

-(-452k+19)



We get rid of parentheses

452k-19=0

We move all terms containing k to the left, all other terms to the right

452k=19

k=19/452

k=19/452

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