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-9/2x=-9-5x
We move all terms to the left:
-9/2x-(-9-5x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-9/2x-(-5x-9)=0
We get rid of parentheses
-9/2x+5x+9=0
We multiply all the terms by the denominator
5x*2x+9*2x-9=0
Wy multiply elements
10x^2+18x-9=0
a = 10; b = 18; c = -9;
Δ = b2-4ac
Δ = 182-4·10·(-9)
Δ = 684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{684}=\sqrt{36*19}=\sqrt{36}*\sqrt{19}=6\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{19}}{2*10}=\frac{-18-6\sqrt{19}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{19}}{2*10}=\frac{-18+6\sqrt{19}}{20} $
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