-9-3(k+5)=9-3(k+11)

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Solution for -9-3(k+5)=9-3(k+11) equation: 



-9-3(k+5)=9-3(k+11)

We move all terms to the left:

-9-3(k+5)-(9-3(k+11))=0

We multiply parentheses

-3k-(9-3(k+11))-15-9=0



We calculate terms in parentheses: -(9-3(k+11)), so:

9-3(k+11)

determiningTheFunctionDomain
-3(k+11)+9

We multiply parentheses

-3k-33+9

We add all the numbers together, and all the variables

-3k-24

Back to the equation:

-(-3k-24)



We add all the numbers together, and all the variables

-3k-(-3k-24)-24=0

We get rid of parentheses

-3k+3k+24-24=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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