-9(y-5)-10=3y-(y-5)

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Solution for -9(y-5)-10=3y-(y-5) equation: 



-9(y-5)-10=3y-(y-5)

We move all terms to the left:

-9(y-5)-10-(3y-(y-5))=0

We multiply parentheses

-9y-(3y-(y-5))+45-10=0



We calculate terms in parentheses: -(3y-(y-5)), so:

3y-(y-5)

We get rid of parentheses

3y-y+5

We add all the numbers together, and all the variables

2y+5

Back to the equation:

-(2y+5)



We add all the numbers together, and all the variables

-9y-(2y+5)+35=0

We get rid of parentheses

-9y-2y-5+35=0

We add all the numbers together, and all the variables

-11y+30=0

We move all terms containing y to the left, all other terms to the right

-11y=-30

y=-30/-11

y=2+8/11

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