-9(x+1)+5(3x-4)=5(x-3)+11

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Solution for -9(x+1)+5(3x-4)=5(x-3)+11 equation: 



-9(x+1)+5(3x-4)=5(x-3)+11

We move all terms to the left:

-9(x+1)+5(3x-4)-(5(x-3)+11)=0

We multiply parentheses

-9x+15x-(5(x-3)+11)-9-20=0



We calculate terms in parentheses: -(5(x-3)+11), so:

5(x-3)+11

We multiply parentheses

5x-15+11

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

6x-(5x-4)-29=0

We get rid of parentheses

6x-5x+4-29=0

We add all the numbers together, and all the variables

x-25=0

We move all terms containing x to the left, all other terms to the right

x=25

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