-9(k+8)=3(1-3k)=2

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Solution for -9(k+8)=3(1-3k)=2 equation: 



-9(k+8)=3(1-3k)=2

We move all terms to the left:

-9(k+8)-(3(1-3k))=0

We add all the numbers together, and all the variables

-9(k+8)-(3(-3k+1))=0

We multiply parentheses

-9k-(3(-3k+1))-72=0



We calculate terms in parentheses: -(3(-3k+1)), so:

3(-3k+1)

We multiply parentheses

-9k+3

Back to the equation:

-(-9k+3)



We get rid of parentheses

-9k+9k-3-72=0

We add all the numbers together, and all the variables

-75!=0

There is no solution for this equation

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