-8y+6(y+2)=10

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Solution for -8y+6(y+2)=10 equation: 



-8y+6(y+2)=10

We move all terms to the left:

-8y+6(y+2)-(10)=0

We multiply parentheses

-8y+6y+12-10=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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