-8x+40=2+3(6-4x)

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Solution for -8x+40=2+3(6-4x) equation: 



-8x+40=2+3(6-4x)

We move all terms to the left:

-8x+40-(2+3(6-4x))=0

We add all the numbers together, and all the variables

-8x-(2+3(-4x+6))+40=0



We calculate terms in parentheses: -(2+3(-4x+6)), so:

2+3(-4x+6)

determiningTheFunctionDomain
3(-4x+6)+2

We multiply parentheses

-12x+18+2

We add all the numbers together, and all the variables

-12x+20

Back to the equation:

-(-12x+20)



We get rid of parentheses

-8x+12x-20+40=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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