-8x+40/x=3

Solution for -8x+40/x=3 equation:

-8x+40/x=3

We move all terms to the left:

-8x+40/x-(3)=0


Domain of the equation: x!=0

x∈R


We multiply all the terms by the denominator


-8x*x-3*x+40=0

We add all the numbers together, and all the variables

-3x-8x*x+40=0

Wy multiply elements

-8x^2-3x+40=0

a = -8; b = -3; c = +40;
Δ = b2-4ac
Δ = -32-4·(-8)·40
Δ = 1289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1289}}{2*-8}=\frac{3-\sqrt{1289}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1289}}{2*-8}=\frac{3+\sqrt{1289}}{-16}
$