-8x(x+6)=-2(4x+24)

Solution for -8x(x+6)=-2(4x+24) equation:

-8x(x+6)=-2(4x+24)

We move all terms to the left:

-8x(x+6)-(-2(4x+24))=0

We multiply parentheses

-8x^2-48x-(-2(4x+24))=0


We calculate terms in parentheses: -(-2(4x+24)), so:

-2(4x+24)

We multiply parentheses

-8x-48

Back to the equation:

-(-8x-48)


We get rid of parentheses

-8x^2-48x+8x+48=0

We add all the numbers together, and all the variables

-8x^2-40x+48=0

a = -8; b = -40; c = +48;
Δ = b2-4ac
Δ = -402-4·(-8)·48
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-56}{2*-8}=\frac{-16}{-16}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+56}{2*-8}=\frac{96}{-16}
=-6
$