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-8k^2+288=0
a = -8; b = 0; c = +288;
Δ = b2-4ac
Δ = 02-4·(-8)·288
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-8}=\frac{-96}{-16} =+6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-8}=\frac{96}{-16} =-6 $
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