-8c(c-10)=-(c-3)

Solution for -8c(c-10)=-(c-3) equation:

-8c(c-10)=-(c-3)

We move all terms to the left:

-8c(c-10)-(-(c-3))=0

We multiply parentheses

-8c^2+80c-(-(c-3))=0


We calculate terms in parentheses: -(-(c-3)), so:

-(c-3)

We get rid of parentheses

-c+3

We add all the numbers together, and all the variables

-1c+3

Back to the equation:

-(-1c+3)


We get rid of parentheses

-8c^2+80c+1c-3=0

We add all the numbers together, and all the variables

-8c^2+81c-3=0

a = -8; b = 81; c = -3;
Δ = b2-4ac
Δ = 812-4·(-8)·(-3)
Δ = 6465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-\sqrt{6465}}{2*-8}=\frac{-81-\sqrt{6465}}{-16}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+\sqrt{6465}}{2*-8}=\frac{-81+\sqrt{6465}}{-16}
$