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-8b^2-3b+22=0
a = -8; b = -3; c = +22;
Δ = b2-4ac
Δ = -32-4·(-8)·22
Δ = 713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{713}}{2*-8}=\frac{3-\sqrt{713}}{-16} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{713}}{2*-8}=\frac{3+\sqrt{713}}{-16} $
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