-8b+2(6b-3)=6b+8(b-2)

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Solution for -8b+2(6b-3)=6b+8(b-2) equation: 



-8b+2(6b-3)=6b+8(b-2)

We move all terms to the left:

-8b+2(6b-3)-(6b+8(b-2))=0

We multiply parentheses

-8b+12b-(6b+8(b-2))-6=0



We calculate terms in parentheses: -(6b+8(b-2)), so:

6b+8(b-2)

We multiply parentheses

6b+8b-16

We add all the numbers together, and all the variables

14b-16

Back to the equation:

-(14b-16)



We add all the numbers together, and all the variables

4b-(14b-16)-6=0

We get rid of parentheses

4b-14b+16-6=0

We add all the numbers together, and all the variables

-10b+10=0

We move all terms containing b to the left, all other terms to the right

-10b=-10

b=-10/-10

b=1

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