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-83=2-5(1+2x)
We move all terms to the left:
-83-(2-5(1+2x))=0
We add all the numbers together, and all the variables
-(2-5(2x+1))-83=0
We calculate terms in parentheses: -(2-5(2x+1)), so:We get rid of parentheses
2-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+2
We multiply parentheses
-10x-5+2
We add all the numbers together, and all the variables
-10x-3
Back to the equation:
-(-10x-3)
10x+3-83=0
We add all the numbers together, and all the variables
10x-80=0
We move all terms containing x to the left, all other terms to the right
10x=80
x=80/10
x=8
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