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-8-2/9x=1/3x-6
We move all terms to the left:
-8-2/9x-(1/3x-6)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 3x-6)!=0We get rid of parentheses
x∈R
-2/9x-1/3x+6-8=0
We calculate fractions
(-6x)/27x^2+(-9x)/27x^2+6-8=0
We add all the numbers together, and all the variables
(-6x)/27x^2+(-9x)/27x^2-2=0
We multiply all the terms by the denominator
(-6x)+(-9x)-2*27x^2=0
Wy multiply elements
-54x^2+(-6x)+(-9x)=0
We get rid of parentheses
-54x^2-6x-9x=0
We add all the numbers together, and all the variables
-54x^2-15x=0
a = -54; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-54)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-54}=\frac{0}{-108} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-54}=\frac{30}{-108} =-5/18 $
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