-8-(-2a+2)=1/3(3-6a)-7

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Solution for -8-(-2a+2)=1/3(3-6a)-7 equation: 



-8-(-2a+2)=1/3(3-6a)-7

We move all terms to the left:

-8-(-2a+2)-(1/3(3-6a)-7)=0



Domain of the equation: 3(3-6a)-7)!=0

a∈R



We add all the numbers together, and all the variables

-(-2a+2)-(1/3(-6a+3)-7)-8=0

We get rid of parentheses

2a-(1/3(-6a+3)-7)-2-8=0

We multiply all the terms by the denominator


2a*3(-6a+3)-2*3(-6a+3)-6a-7)-(1-7)-8*3(+3)-7)=0

We add all the numbers together, and all the variables

2a*3(-6a+3)-2*3(-6a+3)-6a-7)-(-6)-8*33-7)=0

We add all the numbers together, and all the variables

-6a+2a*3(-6a+3)-2*3(-6a+3)=0

Wy multiply elements

6a^2(--6a(--6a=0

We use the square of the difference formula

6a^2(+6a(+6a=0

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