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-8+2X^2+15X=0
a = 2; b = 15; c = -8;
Δ = b2-4ac
Δ = 152-4·2·(-8)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-17}{2*2}=\frac{-32}{4} =-8 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+17}{2*2}=\frac{2}{4} =1/2 $
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