-8(z+4)=7(z+-4)+-3

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Solution for -8(z+4)=7(z+-4)+-3 equation: 



-8(z+4)=7(z+-4)+-3

We move all terms to the left:

-8(z+4)-(7(z+-4)+-3)=0

We add all the numbers together, and all the variables

-8(z+4)-(7(z-4)+-3)=0

We use the square of the difference formula

-8(z+4)-(7(z-4)-3)=0

We multiply parentheses

-8z-(7(z-4)-3)-32=0



We calculate terms in parentheses: -(7(z-4)-3), so:

7(z-4)-3

We multiply parentheses

7z-28-3

We add all the numbers together, and all the variables

7z-31

Back to the equation:

-(7z-31)



We get rid of parentheses

-8z-7z+31-32=0

We add all the numbers together, and all the variables

-15z-1=0

We move all terms containing z to the left, all other terms to the right

-15z=1

z=1/-15

z=-1/15

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