-8(x-4)=6(1-x)

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Solution for -8(x-4)=6(1-x) equation: 



-8(x-4)=6(1-x)

We move all terms to the left:

-8(x-4)-(6(1-x))=0

We add all the numbers together, and all the variables

-8(x-4)-(6(-1x+1))=0

We multiply parentheses

-8x-(6(-1x+1))+32=0



We calculate terms in parentheses: -(6(-1x+1)), so:

6(-1x+1)

We multiply parentheses

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

-8x+6x-6+32=0

We add all the numbers together, and all the variables

-2x+26=0

We move all terms containing x to the left, all other terms to the right

-2x=-26

x=-26/-2

x=+13

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