-8(x+2)+4(3x-5)=3(x-3)+14

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Solution for -8(x+2)+4(3x-5)=3(x-3)+14 equation: 



-8(x+2)+4(3x-5)=3(x-3)+14

We move all terms to the left:

-8(x+2)+4(3x-5)-(3(x-3)+14)=0

We multiply parentheses

-8x+12x-(3(x-3)+14)-16-20=0



We calculate terms in parentheses: -(3(x-3)+14), so:

3(x-3)+14

We multiply parentheses

3x-9+14

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

4x-(3x+5)-36=0

We get rid of parentheses

4x-3x-5-36=0

We add all the numbers together, and all the variables

x-41=0

We move all terms containing x to the left, all other terms to the right

x=41

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