-8(t-2)-(t+4)=3

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Solution for -8(t-2)-(t+4)=3 equation: 



-8(t-2)-(t+4)=3

We move all terms to the left:

-8(t-2)-(t+4)-(3)=0

We multiply parentheses

-8t-(t+4)+16-3=0

We get rid of parentheses

-8t-t-4+16-3=0

We add all the numbers together, and all the variables

-9t+9=0

We move all terms containing t to the left, all other terms to the right

-9t=-9

t=-9/-9

t=1

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