-8(n-6)+3(1+6n)=41

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Solution for -8(n-6)+3(1+6n)=41 equation: 



-8(n-6)+3(1+6n)=41

We move all terms to the left:

-8(n-6)+3(1+6n)-(41)=0

We add all the numbers together, and all the variables

-8(n-6)+3(6n+1)-41=0

We multiply parentheses

-8n+18n+48+3-41=0

We add all the numbers together, and all the variables

10n+10=0

We move all terms containing n to the left, all other terms to the right

10n=-10

n=-10/10

n=-1

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