-8(35x+40)=-16(1+17x)11x

Solution for -8(35x+40)=-16(1+17x)11x equation:

-8(35x+40)=-16(1+17x)11x

We move all terms to the left:

-8(35x+40)-(-16(1+17x)11x)=0

We add all the numbers together, and all the variables

-8(35x+40)-(-16(17x+1)11x)=0

We multiply parentheses

-280x-(-16(17x+1)11x)-320=0


We calculate terms in parentheses: -(-16(17x+1)11x), so:

-16(17x+1)11x

We multiply parentheses

-2992x^2-176x

Back to the equation:

-(-2992x^2-176x)


We get rid of parentheses

2992x^2+176x-280x-320=0

We add all the numbers together, and all the variables

2992x^2-104x-320=0

a = 2992; b = -104; c = -320;
Δ = b2-4ac
Δ = -1042-4·2992·(-320)
Δ = 3840576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3840576}=\sqrt{64*60009}=\sqrt{64}*\sqrt{60009}=8\sqrt{60009}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-8\sqrt{60009}}{2*2992}=\frac{104-8\sqrt{60009}}{5984}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+8\sqrt{60009}}{2*2992}=\frac{104+8\sqrt{60009}}{5984}
$