-8(3-2m)=6(1+m)

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Solution for -8(3-2m)=6(1+m) equation: 



-8(3-2m)=6(1+m)

We move all terms to the left:

-8(3-2m)-(6(1+m))=0

We add all the numbers together, and all the variables

-8(-2m+3)-(6(m+1))=0

We multiply parentheses

16m-(6(m+1))-24=0



We calculate terms in parentheses: -(6(m+1)), so:

6(m+1)

We multiply parentheses

6m+6

Back to the equation:

-(6m+6)



We get rid of parentheses

16m-6m-6-24=0

We add all the numbers together, and all the variables

10m-30=0

We move all terms containing m to the left, all other terms to the right

10m=30

m=30/10

m=3

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