-8(3+x)+3(3-x)-5=-6-10(x+2)

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Solution for -8(3+x)+3(3-x)-5=-6-10(x+2) equation: 



-8(3+x)+3(3-x)-5=-6-10(x+2)

We move all terms to the left:

-8(3+x)+3(3-x)-5-(-6-10(x+2))=0

We add all the numbers together, and all the variables

-8(x+3)+3(-1x+3)-(-6-10(x+2))-5=0

We multiply parentheses

-8x-3x-(-6-10(x+2))-24+9-5=0



We calculate terms in parentheses: -(-6-10(x+2)), so:

-6-10(x+2)

determiningTheFunctionDomain
-10(x+2)-6

We multiply parentheses

-10x-20-6

We add all the numbers together, and all the variables

-10x-26

Back to the equation:

-(-10x-26)



We add all the numbers together, and all the variables

-11x-(-10x-26)-20=0

We get rid of parentheses

-11x+10x+26-20=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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