-8(2z-5)+10z=-5z

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Solution for -8(2z-5)+10z=-5z equation: 



-8(2z-5)+10z=-5z

We move all terms to the left:

-8(2z-5)+10z-(-5z)=0

We add all the numbers together, and all the variables

10z-8(2z-5)-(-5z)=0

We multiply parentheses

10z-16z-(-5z)+40=0

We get rid of parentheses

10z-16z+5z+40=0

We add all the numbers together, and all the variables

-1z+40=0

We move all terms containing z to the left, all other terms to the right

-z=-40

z=-40/-1

z=+40

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