-8(2i-4)=9(4-2i)

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Solution for -8(2i-4)=9(4-2i) equation: 



-8(2i-4)=9(4-2i)

We move all terms to the left:

-8(2i-4)-(9(4-2i))=0

We add all the numbers together, and all the variables

-8(2i-4)-(9(-2i+4))=0

We multiply parentheses

-16i-(9(-2i+4))+32=0



We calculate terms in parentheses: -(9(-2i+4)), so:

9(-2i+4)

We multiply parentheses

-18i+36

Back to the equation:

-(-18i+36)



We get rid of parentheses

-16i+18i-36+32=0

We add all the numbers together, and all the variables

2i-4=0

We move all terms containing i to the left, all other terms to the right

2i=4

i=4/2

i=2

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