-8(17+4c)+16=3(3c-11)

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Solution for -8(17+4c)+16=3(3c-11) equation: 



-8(17+4c)+16=3(3c-11)

We move all terms to the left:

-8(17+4c)+16-(3(3c-11))=0

We add all the numbers together, and all the variables

-8(4c+17)-(3(3c-11))+16=0

We multiply parentheses

-32c-(3(3c-11))-136+16=0



We calculate terms in parentheses: -(3(3c-11)), so:

3(3c-11)

We multiply parentheses

9c-33

Back to the equation:

-(9c-33)



We add all the numbers together, and all the variables

-32c-(9c-33)-120=0

We get rid of parentheses

-32c-9c+33-120=0

We add all the numbers together, and all the variables

-41c-87=0

We move all terms containing c to the left, all other terms to the right

-41c=87

c=87/-41

c=-2+5/41

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