-8(11-2)+40=3(5x-4)

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Solution for -8(11-2)+40=3(5x-4) equation: 



-8(11-2)+40=3(5x-4)

We move all terms to the left:

-8(11-2)+40-(3(5x-4))=0

We add all the numbers together, and all the variables

-(3(5x-4))+40-89=0

We add all the numbers together, and all the variables

-(3(5x-4))-49=0



We calculate terms in parentheses: -(3(5x-4)), so:

3(5x-4)

We multiply parentheses

15x-12

Back to the equation:

-(15x-12)



We get rid of parentheses

-15x+12-49=0

We add all the numbers together, and all the variables

-15x-37=0

We move all terms containing x to the left, all other terms to the right

-15x=37

x=37/-15

x=-2+7/15

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