-7z-(15z+3)=3+(7z+8)

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Solution for -7z-(15z+3)=3+(7z+8) equation: 



-7z-(15z+3)=3+(7z+8)

We move all terms to the left:

-7z-(15z+3)-(3+(7z+8))=0

We get rid of parentheses

-7z-15z-(3+(7z+8))-3=0



We calculate terms in parentheses: -(3+(7z+8)), so:

3+(7z+8)

determiningTheFunctionDomain
(7z+8)+3

We get rid of parentheses

7z+8+3

We add all the numbers together, and all the variables

7z+11

Back to the equation:

-(7z+11)



We add all the numbers together, and all the variables

-22z-(7z+11)-3=0

We get rid of parentheses

-22z-7z-11-3=0

We add all the numbers together, and all the variables

-29z-14=0

We move all terms containing z to the left, all other terms to the right

-29z=14

z=14/-29

z=-14/29

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