-7z-(11z+5)=5+(3z+2)

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Solution for -7z-(11z+5)=5+(3z+2) equation: 



-7z-(11z+5)=5+(3z+2)

We move all terms to the left:

-7z-(11z+5)-(5+(3z+2))=0

We get rid of parentheses

-7z-11z-(5+(3z+2))-5=0



We calculate terms in parentheses: -(5+(3z+2)), so:

5+(3z+2)

determiningTheFunctionDomain
(3z+2)+5

We get rid of parentheses

3z+2+5

We add all the numbers together, and all the variables

3z+7

Back to the equation:

-(3z+7)



We add all the numbers together, and all the variables

-18z-(3z+7)-5=0

We get rid of parentheses

-18z-3z-7-5=0

We add all the numbers together, and all the variables

-21z-12=0

We move all terms containing z to the left, all other terms to the right

-21z=12

z=12/-21

z=-4/7

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