-7y+3(y+2)=2

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Solution for -7y+3(y+2)=2 equation: 



-7y+3(y+2)=2

We move all terms to the left:

-7y+3(y+2)-(2)=0

We multiply parentheses

-7y+3y+6-2=0

We add all the numbers together, and all the variables

-4y+4=0

We move all terms containing y to the left, all other terms to the right

-4y=-4

y=-4/-4

y=1

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