-7x-60=x2+10x

Solution for -7x-60=x2+10x equation:

-7x-60=x2+10x

We move all terms to the left:

-7x-60-(x2+10x)=0

We add all the numbers together, and all the variables

-(+x^2+10x)-7x-60=0

We get rid of parentheses

-x^2-10x-7x-60=0

We add all the numbers together, and all the variables

-1x^2-17x-60=0

a = -1; b = -17; c = -60;
Δ = b2-4ac
Δ = -172-4·(-1)·(-60)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*-1}=\frac{10}{-2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*-1}=\frac{24}{-2}
=-12
$