-7x-4(7-4x)=5x-40

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Solution for -7x-4(7-4x)=5x-40 equation: 



-7x-4(7-4x)=5x-40

We move all terms to the left:

-7x-4(7-4x)-(5x-40)=0

We add all the numbers together, and all the variables

-7x-4(-4x+7)-(5x-40)=0

We multiply parentheses

-7x+16x-(5x-40)-28=0

We get rid of parentheses

-7x+16x-5x+40-28=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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