-7x+3(x-4)=6(x-5)+8

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Solution for -7x+3(x-4)=6(x-5)+8 equation: 



-7x+3(x-4)=6(x-5)+8

We move all terms to the left:

-7x+3(x-4)-(6(x-5)+8)=0

We multiply parentheses

-7x+3x-(6(x-5)+8)-12=0



We calculate terms in parentheses: -(6(x-5)+8), so:

6(x-5)+8

We multiply parentheses

6x-30+8

We add all the numbers together, and all the variables

6x-22

Back to the equation:

-(6x-22)



We add all the numbers together, and all the variables

-4x-(6x-22)-12=0

We get rid of parentheses

-4x-6x+22-12=0

We add all the numbers together, and all the variables

-10x+10=0

We move all terms containing x to the left, all other terms to the right

-10x=-10

x=-10/-10

x=1

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