-7x+29=6(8+3x)x=

Solution for -7x+29=6(8+3x)x= equation:

-7x+29=6(8+3x)x=

We move all terms to the left:

-7x+29-(6(8+3x)x)=0

We add all the numbers together, and all the variables

-7x-(6(3x+8)x)+29=0


We calculate terms in parentheses: -(6(3x+8)x), so:

6(3x+8)x

We multiply parentheses

18x^2+48x

Back to the equation:

-(18x^2+48x)


We get rid of parentheses

-18x^2-7x-48x+29=0

We add all the numbers together, and all the variables

-18x^2-55x+29=0

a = -18; b = -55; c = +29;
Δ = b2-4ac
Δ = -552-4·(-18)·29
Δ = 5113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{5113}}{2*-18}=\frac{55-\sqrt{5113}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{5113}}{2*-18}=\frac{55+\sqrt{5113}}{-36}
$