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-7x(x+3)=-2(x+3)-5x
We move all terms to the left:
-7x(x+3)-(-2(x+3)-5x)=0
We multiply parentheses
-7x^2-21x-(-2(x+3)-5x)=0
We calculate terms in parentheses: -(-2(x+3)-5x), so:We get rid of parentheses
-2(x+3)-5x
We add all the numbers together, and all the variables
-5x-2(x+3)
We multiply parentheses
-5x-2x-6
We add all the numbers together, and all the variables
-7x-6
Back to the equation:
-(-7x-6)
-7x^2-21x+7x+6=0
We add all the numbers together, and all the variables
-7x^2-14x+6=0
a = -7; b = -14; c = +6;
Δ = b2-4ac
Δ = -142-4·(-7)·6
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{91}}{2*-7}=\frac{14-2\sqrt{91}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{91}}{2*-7}=\frac{14+2\sqrt{91}}{-14} $
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