-7=3(n-5)-n

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Solution for -7=3(n-5)-n equation: 



-7=3(n-5)-n

We move all terms to the left:

-7-(3(n-5)-n)=0



We calculate terms in parentheses: -(3(n-5)-n), so:

3(n-5)-n

We add all the numbers together, and all the variables

-1n+3(n-5)

We multiply parentheses

-1n+3n-15

We add all the numbers together, and all the variables

2n-15

Back to the equation:

-(2n-15)



We get rid of parentheses

-2n+15-7=0

We add all the numbers together, and all the variables

-2n+8=0

We move all terms containing n to the left, all other terms to the right

-2n=-8

n=-8/-2

n=+4

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