-7=2(j-6)+-7=

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Solution for -7=2(j-6)+-7= equation: 



-7=2(j-6)+-7=

We move all terms to the left:

-7-(2(j-6)+-7)=0

We use the square of the difference formula

-(2(j-6)-7)-7=0



We calculate terms in parentheses: -(2(j-6)-7), so:

2(j-6)-7

We multiply parentheses

2j-12-7

We add all the numbers together, and all the variables

2j-19

Back to the equation:

-(2j-19)



We get rid of parentheses

-2j+19-7=0

We add all the numbers together, and all the variables

-2j+12=0

We move all terms containing j to the left, all other terms to the right

-2j=-12

j=-12/-2

j=+6

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