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-7=1/5h
We move all terms to the left:
-7-(1/5h)=0
Domain of the equation: 5h)!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
-(+1/5h)-7=0
We get rid of parentheses
-1/5h-7=0
We multiply all the terms by the denominator
-7*5h-1=0
Wy multiply elements
-35h-1=0
We move all terms containing h to the left, all other terms to the right
-35h=1
h=1/-35
h=-1/35
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