-7=(3/2)(r)+5

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Solution for -7=(3/2)(r)+5 equation: 



-7=(3/2)(r)+5

We move all terms to the left:

-7-((3/2)(r)+5)=0



Domain of the equation: 2)r+5)!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

-((+3/2)r+5)-7=0

We multiply all the terms by the denominator


-((+3-7*2)r+5)=0



We calculate terms in parentheses: -((+3-7*2)r+5), so:

(+3-7*2)r+5

We add all the numbers together, and all the variables

(-11)r+5

We multiply parentheses

-11r+5

Back to the equation:

-(-11r+5)



We get rid of parentheses

11r-5=0

We move all terms containing r to the left, all other terms to the right

11r=5

r=5/11

r=5/11

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