-7=(-3-(-5x))/(2+3x)

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Solution for -7=(-3-(-5x))/(2+3x) equation: 



-7=(-3-(-5x))/(2+3x)

We move all terms to the left:

-7-((-3-(-5x))/(2+3x))=0



Domain of the equation: (2+3x))!=0

We move all terms containing x to the left, all other terms to the right

3x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

-((-3-(-5x))/(3x+2))-7=0

We multiply all the terms by the denominator


-((-3-(-5x))-7*(3x+2))=0



We calculate terms in parentheses: -((-3-(-5x))-7*(3x+2)), so:

(-3-(-5x))-7*(3x+2)

We multiply parentheses

(-3-(-5x))-21x-14



We calculate terms in parentheses: +(-3-(-5x)), so:

-3-(-5x)

determiningTheFunctionDomain
-(-5x)-3

We get rid of parentheses

5x-3

Back to the equation:

+(5x-3)



We add all the numbers together, and all the variables

-21x+(5x-3)-14

We get rid of parentheses

-21x+5x-3-14

We add all the numbers together, and all the variables

-16x-17

Back to the equation:

-(-16x-17)



We get rid of parentheses

16x+17=0

We move all terms containing x to the left, all other terms to the right

16x=-17

x=-17/16

x=-1+1/16

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