-78=7(b+1)-8

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Solution for -78=7(b+1)-8 equation:



-78=7(b+1)-8
We move all terms to the left:
-78-(7(b+1)-8)=0
We calculate terms in parentheses: -(7(b+1)-8), so:
7(b+1)-8
We multiply parentheses
7b+7-8
We add all the numbers together, and all the variables
7b-1
Back to the equation:
-(7b-1)
We get rid of parentheses
-7b+1-78=0
We add all the numbers together, and all the variables
-7b-77=0
We move all terms containing b to the left, all other terms to the right
-7b=77
b=77/-7
b=-11

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