-71+7z=-7+-3(4z+-4)

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Solution for -71+7z=-7+-3(4z+-4) equation: 



-71+7z=-7+-3(4z+-4)

We move all terms to the left:

-71+7z-(-7+-3(4z+-4))=0

We add all the numbers together, and all the variables

7z-(-7+-3(4z-4))-71=0

We use the square of the difference formula

7z-(-7-3(4z-4))-71=0



We calculate terms in parentheses: -(-7-3(4z-4)), so:

-7-3(4z-4)

determiningTheFunctionDomain
-3(4z-4)-7

We multiply parentheses

-12z+12-7

We add all the numbers together, and all the variables

-12z+5

Back to the equation:

-(-12z+5)



We get rid of parentheses

7z+12z-5-71=0

We add all the numbers together, and all the variables

19z-76=0

We move all terms containing z to the left, all other terms to the right

19z=76

z=76/19

z=4

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