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-7/5k+6/7=8+5/7k
We move all terms to the left:
-7/5k+6/7-(8+5/7k)=0
Domain of the equation: 5k!=0
k!=0/5
k!=0
k∈R
Domain of the equation: 7k)!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
-7/5k-(5/7k+8)+6/7=0
We get rid of parentheses
-7/5k-5/7k-8+6/7=0
We calculate fractions
(-2401k)/1715k^2+(-25k)/1715k^2+30k/1715k^2-8=0
We multiply all the terms by the denominator
(-2401k)+(-25k)+30k-8*1715k^2=0
We add all the numbers together, and all the variables
30k+(-2401k)+(-25k)-8*1715k^2=0
Wy multiply elements
-13720k^2+30k+(-2401k)+(-25k)=0
We get rid of parentheses
-13720k^2+30k-2401k-25k=0
We add all the numbers together, and all the variables
-13720k^2-2396k=0
a = -13720; b = -2396; c = 0;
Δ = b2-4ac
Δ = -23962-4·(-13720)·0
Δ = 5740816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5740816}=2396$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2396)-2396}{2*-13720}=\frac{0}{-27440} =0 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2396)+2396}{2*-13720}=\frac{4792}{-27440} =-599/3430 $
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