-7/4x+3/2x=-5/14

Solution for -7/4x+3/2x=-5/14 equation:

-7/4x+3/2x=-5/14

We move all terms to the left:

-7/4x+3/2x-(-5/14)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

-7/4x+3/2x+5/14=0

We calculate fractions


80x^2/112x^2+(-196x)/112x^2+168x/112x^2=0

We multiply all the terms by the denominator


80x^2+(-196x)+168x=0

We add all the numbers together, and all the variables

80x^2+168x+(-196x)=0

We get rid of parentheses

80x^2+168x-196x=0

We add all the numbers together, and all the variables

80x^2-28x=0

a = 80; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·80·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*80}=\frac{0}{160}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*80}=\frac{56}{160}
=7/20
$