-7/3x+5/4x=2

Solution for -7/3x+5/4x=2 equation:

-7/3x+5/4x=2

We move all terms to the left:

-7/3x+5/4x-(2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


(-28x)/12x^2+15x/12x^2-2=0

We multiply all the terms by the denominator


(-28x)+15x-2*12x^2=0

We add all the numbers together, and all the variables

15x+(-28x)-2*12x^2=0

Wy multiply elements

-24x^2+15x+(-28x)=0

We get rid of parentheses

-24x^2+15x-28x=0

We add all the numbers together, and all the variables

-24x^2-13x=0

a = -24; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·(-24)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*-24}=\frac{0}{-48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*-24}=\frac{26}{-48}
=-13/24
$