-7/10h-4/5h=-30

Solution for -7/10h-4/5h=-30 equation:

-7/10h-4/5h=-30

We move all terms to the left:

-7/10h-4/5h-(-30)=0


Domain of the equation: 10h!=0

h!=0/10

h!=0

h∈R



Domain of the equation: 5h!=0

h!=0/5

h!=0

h∈R


We add all the numbers together, and all the variables

-7/10h-4/5h+30=0

We calculate fractions


(-35h)/50h^2+(-40h)/50h^2+30=0

We multiply all the terms by the denominator


(-35h)+(-40h)+30*50h^2=0

Wy multiply elements

1500h^2+(-35h)+(-40h)=0

We get rid of parentheses

1500h^2-35h-40h=0

We add all the numbers together, and all the variables

1500h^2-75h=0

a = 1500; b = -75; c = 0;
Δ = b2-4ac
Δ = -752-4·1500·0
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-75}{2*1500}=\frac{0}{3000}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+75}{2*1500}=\frac{150}{3000}
=1/20
$