-7+7(8m-6)=2(1+3m)-1

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Solution for -7+7(8m-6)=2(1+3m)-1 equation: 



-7+7(8m-6)=2(1+3m)-1

We move all terms to the left:

-7+7(8m-6)-(2(1+3m)-1)=0

We add all the numbers together, and all the variables

7(8m-6)-(2(3m+1)-1)-7=0

We multiply parentheses

56m-(2(3m+1)-1)-42-7=0



We calculate terms in parentheses: -(2(3m+1)-1), so:

2(3m+1)-1

We multiply parentheses

6m+2-1

We add all the numbers together, and all the variables

6m+1

Back to the equation:

-(6m+1)



We add all the numbers together, and all the variables

56m-(6m+1)-49=0

We get rid of parentheses

56m-6m-1-49=0

We add all the numbers together, and all the variables

50m-50=0

We move all terms containing m to the left, all other terms to the right

50m=50

m=50/50

m=1

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